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  • https://ukrayinska.libretexts.org/%D1%84%D1%96%D0%B7%D0%B8%D0%BA%D0%B8/%D0%9A%D0%BB%D0%B0%D1%81%D0%B8%D1%87%D0%BD%D0%B0_%D0%BC%D0%B5%D1%85%D0%B0%D0%BD%D1%96%D0%BA%D0%B0/%D0%9A%D0%BB%D0%B0%D1%81%D0%B8%D1%87%D0%BD%D0%B0_%D0%BC%D0%B5%D1%85%D0%B0%D0%BD%D1%96%D0%BA%D0%B0_(Tatum)/17%3A_%D0%92%D1%96%D0%B1%D1%80%D0%B0%D1%86%D1%96%D0%B9%D0%BD%D1%96_%D1%81%D0%B8%D1%81%D1%82%D0%B5%D0%BC%D0%B8/17.13%3A_%D0%94%D0%B5%D0%BC%D0%BF%D1%84%D1%96%D1%80%D0%BE%D0%B2%D0%B0%D0%BD%D0%B0_%D0%BA%D0%B5%D1%80%D0%BE%D0%B2%D0%B0%D0%BD%D0%B0_%D1%81%D0%B8%D1%81%D1%82%D0%B5%D0%BC%D0%B0
    ˆx2=((k1 + k2 mω2) + b2ω2)ˆF2((k1mω2)2+ b2ω2)((k1+2k2mω2)2+ b2ω2)...\boldsymbol{\hat{x}^{2}=\frac{((k_{1}\ +\ k_{2}\ -m\omega^{2})\ +\ b^{2}\omega^{2})\hat{F}^{2}}{((k_{1}-m\omega^{2})^{2}+\ b^{2}\omega^{2})((k_{1}+2k_{2}-m\omega^{2})^{2}+\ b^{2}\omega^{2})} \label{17.13.5}} Що стосуєтьсяk2, то я збираюся ввести коефіцієнт зчеплення,α який визначаєтьсяα = k2k1+k2 абоk2 = (α1α)k1.