\[\begin{align} d S &=\frac{1}{T}[d U+P d V] \\[4pt] &=\dfrac{1}{T}\left[\left(\frac{\partial U}{\partial V}\right)_{T} d V+\left(\frac{\partial U}{\partial T}\right)_{V} d T+P d V\right].\\[4pt] &=\f...dS=1T[dU+PdV]=1T[(∂U∂V)TdV+(∂U∂T)VdT+PdV].=1T[(∂U∂V)T+P]dV+1T(∂U∂T)VdT.