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  • https://ukrayinska.libretexts.org/%D1%84%D1%96%D0%B7%D0%B8%D0%BA%D0%B8/%D0%95%D0%BB%D0%B5%D0%BA%D1%82%D1%80%D0%B8%D0%BA%D0%B0_%D1%96_%D0%BC%D0%B0%D0%B3%D0%BD%D0%B5%D1%82%D0%B8%D0%B7%D0%BC/%D0%95%D0%BB%D0%B5%D0%BA%D1%82%D1%80%D0%B8%D0%BA%D0%B0_%D1%96_%D0%BC%D0%B0%D0%B3%D0%BD%D0%B5%D1%82%D0%B8%D0%B7%D0%BC_(Tatum)/14%3A_%D0%9B%D0%B0%D0%BF%D0%BB%D0%B0%D1%81_%D0%BF%D0%B5%D1%80%D0%B5%D1%82%D0%B2%D0%BE%D1%80%D1%8E%D1%94%D1%82%D1%8C%D1%81%D1%8F/14.12%3A_%D0%86%D0%BD%D1%88%D0%B8%D0%B9_%D0%BF%D1%80%D0%B8%D0%BA%D0%BB%D0%B0%D0%B4
    \[R^2C^2\ddot Q_1 + 3 RC Q_1 + Q_1 = CV. \tag{14.12.3}\] Тобто\[R^2C \bar{Q_1}= \frac{1}{s(s+2.618a)(s+0.382a)}V. \tag{14.12.7}\] Часткові дроби:\[R^2C\bar{Q_1} = \left[\frac{1}{s} + \frac{0.1708}{s+2...\[R^2C^2\ddot Q_1 + 3 RC Q_1 + Q_1 = CV. \tag{14.12.3}\] Тобто\[R^2C \bar{Q_1}= \frac{1}{s(s+2.618a)(s+0.382a)}V. \tag{14.12.7}\] Часткові дроби:\[R^2C\bar{Q_1} = \left[\frac{1}{s} + \frac{0.1708}{s+2.618a} - \frac{1.1708}{s+0.382a} \right] \frac{V}{a^2}. \tag{14.12.8}\] Тобто,\[\bar{Q_1} = \left[ \frac{1}{s} + \frac{0.1708}{s+2.618a} - \frac{1.1708}{s+0.382a} \right]CV. \tag{14.12.9}\]