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  • https://ukrayinska.libretexts.org/%D0%9C%D0%B0%D1%82%D0%B5%D0%BC%D0%B0%D1%82%D0%B8%D0%BA%D0%B0/%D1%80%D0%BE%D0%B7%D1%80%D0%B0%D1%85%D1%83%D0%BD%D0%BA%D1%83/%D0%9F%D1%80%D0%B8%D0%BA%D0%BB%D0%B0%D0%B4%D0%BD%D0%B5_%D0%BE%D0%B1%D1%87%D0%B8%D1%81%D0%BB%D0%B5%D0%BD%D0%BD%D1%8F_(Calaway%2C_Hoffman_%D1%82%D0%B0_Lippman)/03%3A_%D0%86%D0%BD%D1%82%D0%B5%D0%B3%D1%80%D0%B0%D0%BB%D1%8C%D0%BD%D0%B0/3.06%3A_%D0%94%D0%BE%D0%B4%D0%B0%D1%82%D0%BA%D0%BE%D0%B2%D1%96_%D0%BC%D0%B5%D1%82%D0%BE%D0%B4%D0%B8_%D1%96%D0%BD%D1%82%D0%B5%D0%B3%D1%80%D0%B0%D1%86%D1%96%D1%97
    \[ \begin{align*} \int \frac{1}{x^2-a^2}\, dx & = \frac{1}{2a}\ln\left|\frac{x-a}{x+a}\right|+C \\ \int \frac{1}{\sqrt{x^2+a^2}}\, dx & = \ln\left|x+\sqrt{x^2+a^2}\right|+C \end{align*} \nonumber \] Т...\[ \begin{align*} \int \frac{1}{x^2-a^2}\, dx & = \frac{1}{2a}\ln\left|\frac{x-a}{x+a}\right|+C \\ \int \frac{1}{\sqrt{x^2+a^2}}\, dx & = \ln\left|x+\sqrt{x^2+a^2}\right|+C \end{align*} \nonumber \] Тепер просто використовуємо формулу з таблиці, з\(a = 3\). \[ \begin{align*} \int\frac{5}{x^2-9}\, dx = & 5\int\frac{1}{x^2-3^2}\, dx \\ & = 5\left(\frac{1}{2\cdot 3}\ln\left|\frac{x-3}{x+3}\right|\right)+C \\ & = \frac{5}{6}\ln\left|\frac{x-3}{x+3}\right|+C \end{align*} \nonumber \]