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  • https://ukrayinska.libretexts.org/%D0%9C%D0%B0%D1%82%D0%B5%D0%BC%D0%B0%D1%82%D0%B8%D0%BA%D0%B0/%D0%90%D0%BD%D0%B0%D0%BB%D1%96%D0%B7/%D0%A1%D0%BA%D0%BB%D0%B0%D0%B4%D0%BD%D1%96_%D0%B7%D0%BC%D1%96%D0%BD%D0%BD%D1%96_%D0%B7_%D0%B4%D0%BE%D0%B4%D0%B0%D1%82%D0%BA%D0%B0%D0%BC%D0%B8_(Orloff)/03%3A_%D0%91%D0%B0%D0%B3%D0%B0%D1%82%D0%BE%D0%B2%D0%B0%D1%80%D1%96%D0%B0%D0%BD%D1%82%D0%BD%D0%B0_%D0%BE%D0%B1%D1%87%D0%B8%D1%81%D0%BB%D0%B5%D0%BD%D0%BD%D1%8F_(%D0%BE%D0%B3%D0%BB%D1%8F%D0%B4)/3.03%3A_%D0%9F%D1%80%D0%B0%D0%B2%D0%B8%D0%BB%D0%BE_%D0%BB%D0%B0%D0%BD%D1%86%D1%8E%D0%B3%D0%B0
    Для функціїf(x,y) таγ(t)=(x(t),y(t)) кривої правило ланцюга дає \[\dfrac{df(\gamma (t))}{dt} = \left. \dfrac{\partial f}{\partial x} \right\vert_{\gamma (t)} x'(t) + \left. \dfrac{\p...Для функціїf(x,y) таγ(t)=(x(t),y(t)) кривої правило ланцюга дає df(γ(t))dt=fx|γ(t)x(t)+fy|γ(t)y(t)=f(γ(t))y(t) dot product of vectors. fОсь градієнт,f визначений у наступному розділі.