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  • https://ukrayinska.libretexts.org/%D0%9C%D0%B0%D1%82%D0%B5%D0%BC%D0%B0%D1%82%D0%B8%D0%BA%D0%B0/%D0%90%D0%BB%D0%B3%D0%B5%D0%B1%D1%80%D0%B0/%D0%9F%D1%80%D0%BE%D0%BC%D1%96%D0%B6%D0%BD%D0%B0_%D0%B0%D0%BB%D0%B3%D0%B5%D0%B1%D1%80%D0%B0_(OpenStax)/06%3A_%D0%A4%D0%B0%D0%BA%D1%82%D0%BE%D1%80%D0%B8%D0%BD%D0%B3/6.05%3A_%D0%97%D0%B0%D0%B3%D0%B0%D0%BB%D1%8C%D0%BD%D0%B0_%D1%81%D1%82%D1%80%D0%B0%D1%82%D0%B5%D0%B3%D1%96%D1%8F_%D1%84%D0%B0%D0%BA%D1%82%D0%BE%D1%80%D0%B8%D0%BD%D0%B3%D1%83_%D0%BF%D0%BE%D0%BB%D1%96%D0%BD%D0%BE%D0%BC%D1%96%D0%B0%D0%BB%D1%8C%D0%BD%D0%B8%D1%85_%D0%B2%D0%B8%D1%80%D0%B0%D0%B7%D1%96%D0%B2
    Of squares or cubes?} \\ \text{Write it as a difference of squares.} \end{array} &3xy\left((x^2)^2−(4)2\right) \\ \text{Factor it as a product of conjugates} &3xy(x^2−4)(x^2+4) \\ \text{The first bino...Of squares or cubes?} \\ \text{Write it as a difference of squares.} \end{array} &3xy\left((x^2)^2−(4)2\right) \\ \text{Factor it as a product of conjugates} &3xy(x^2−4)(x^2+4) \\ \text{The first binomial is again a difference of squares.} &3xy\left((x)^2−(2)^2\right)(x^2+4) \\ \text{Factor it as a product of conjugates.} &3xy(x−2)(x+2)(x^2+4) \\ \text{Is the expression factored completely?