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  • 8.3: Зменшення раціональних виразів
    https://ukrayinska.libretexts.org/%D0%9C%D0%B0%D1%82%D0%B5%D0%BC%D0%B0%D1%82%D0%B8%D0%BA%D0%B0/%D0%90%D0%BB%D0%B3%D0%B5%D0%B1%D1%80%D0%B0/%D0%95%D0%BB%D0%B5%D0%BC%D0%B5%D0%BD%D1%82%D0%B0%D1%80%D0%BD%D0%B0_%D0%B0%D0%BB%D0%B3%D0%B5%D0%B1%D1%80%D0%B0_(Ellis_%D1%96_Burzynski)/08%3A_%D0%A0%D0%B0%D1%86%D1%96%D0%BE%D0%BD%D0%B0%D0%BB%D1%8C%D0%BD%D1%96_%D0%B2%D0%B8%D1%80%D0%B0%D0%B7%D0%B8/8.03%3A_%D0%97%D0%BC%D0%B5%D0%BD%D1%88%D0%B5%D0%BD%D0%BD%D1%8F_%D1%80%D0%B0%D1%86%D1%96%D0%BE%D0%BD%D0%B0%D0%BB%D1%8C%D0%BD%D0%B8%D1%85_%D0%B2%D0%B8%D1%80%D0%B0%D0%B7%D1%96%D0%B2
    \(\dfrac{\not 2 \cdot \not 2 \cdot \not 2 \cdot 2}{\not 2 \cdot \not 2 \cdot \not 2 \cdot 5} = \dfrac{2}{5}\) \ dfrac {-10x^3a (x^2-36)} {2x^3-10x^2-12x} &=\ dfrac {-5\ cdot 2x^3a (x+6)} {2x (x^2 - 5x...\(\dfrac{\not 2 \cdot \not 2 \cdot \not 2 \cdot 2}{\not 2 \cdot \not 2 \cdot \not 2 \cdot 5} = \dfrac{2}{5}\) \ dfrac {-10x^3a (x^2-36)} {2x^3-10x^2-12x} &=\ dfrac {-5\ cdot 2x^3a (x+6)} {2x (x^2 - 5x - 6)}\\ &=\ dfrac {-5\ cdot\ скасувати {2} x^ {\ скасувати {3}} a (x+6)} (x-6)} {\ cancel {2}\ скасувати {x}\ скасувати {(x-6) } (x+1)}\\ \(-\dfrac{x+3}{x+2} = \dfrac{-(x+3)}{x+2} = \dfrac{-x-3}{x+2}, x \not = -2, 4\)