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  • https://ukrayinska.libretexts.org/%D0%9C%D0%B0%D1%82%D0%B5%D0%BC%D0%B0%D1%82%D0%B8%D0%BA%D0%B0/%D0%90%D0%BB%D0%B3%D0%B5%D0%B1%D1%80%D0%B0/%D0%9A%D0%BD%D0%B8%D0%B3%D0%B0%3A_%D0%90%D0%BB%D0%B3%D0%B5%D0%B1%D1%80%D0%B0_%D0%BA%D0%BE%D0%BB%D0%B5%D0%B4%D0%B6%D1%83_%D1%82%D0%B0_%D1%82%D1%80%D0%B8%D0%B3%D0%BE%D0%BD%D0%BE%D0%BC%D0%B5%D1%82%D1%80%D1%96%D1%8F_(Beveridge)/04%3A_%D0%A4%D1%83%D0%BD%D0%BA%D1%86%D1%96%D1%97/407%3A_%D0%9A%D0%BE%D0%BC%D0%BF%D0%BE%D0%B7%D0%B8%D1%82%D0%BD%D1%96_%D1%84%D1%83%D0%BD%D0%BA%D1%86%D1%96%D1%97
    \ text {дорівнює} g\ left (x^ {3}\ праворуч) =2\ left (x^ {3}\ right) -7=2 x^ {3} -7 1)f(x)=x2g(x)=x1 2)f(x)=|x3|g(x)=2x+3 3)\(\quad f(x)=\frac{x}{x-2} \\ g(x)=\frac{...\ text {дорівнює} g\ left (x^ {3}\ праворуч) =2\ left (x^ {3}\ right) -7=2 x^ {3} -7 1)f(x)=x2g(x)=x1 2)f(x)=|x3|g(x)=2x+3 3)f(x)=xx2g(x)=x+3x 4)\boldsymbol{\quad f(x)=x^{3}-1 \\ g(x)=\frac{1}{x^{3}+1} 6)\boldsymbol{\quad f(x)=2 x^{3}-1 \\ g(x)=\sqrt[3]{\frac{x+1}{2}} Знайти функціїf(x) іg(x) так, щоб дана функціяh(x)=fg(x) 12)h(x)=(12x1+2x)3 14)h(x)=(1+1x)2