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11.5E: Вправи
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$\frac{(y+4)^{2}}{25}-\frac{(x+1)^{2}}{36}=1$ $\frac{(y+1)^{2}}{16}-\frac{(x+1)^{2}}{4}=1$ $\frac{(y-4)^{2}}{16}-\frac{(x+1)^{2}}{25}=1$ $\frac{(x+2)^{2}}{4}-\frac{(y-1)^{2}}{9}=1$ \(9 x^{2}-4... $\frac{(y+4)^{2}}{25}-\frac{(x+1)^{2}}{36}=1$ $\frac{(y+1)^{2}}{16}-\frac{(x+1)^{2}}{4}=1$ $\frac{(y-4)^{2}}{16}-\frac{(x+1)^{2}}{25}=1$ $\frac{(x+2)^{2}}{4}-\frac{(y-1)^{2}}{9}=1$ $9 x^{2}-4 y^{2}-18 x+8 y-31=0$ $y^{2}-x^{2}-4 y+2 x-6=0$ $4 y^{2}-16 x^{2}-24 y+96 x-172=0$ $\frac{(y+1)^{2}}{1}-\frac{(x+2)^{2}}{9}=1$ $\frac{(y-3)^{2}}{9}-\frac{(x+2)^{2}}{16}=1$ $x^{2}+y^{2}-4 x+10 y-7=0$ $9 x^{2}-4 y^{2}+54 x+8 y+41=0$ $x=-y^{2}-2 y+3$