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1.7: Порядок операцій
https://ukrayinska.libretexts.org/%D0%9C%D0%B0%D1%82%D0%B5%D0%BC%D0%B0%D1%82%D0%B8%D0%BA%D0%B0/%D0%90%D0%BB%D0%B3%D0%B5%D0%B1%D1%80%D0%B0/%D0%9F%D0%BE%D1%87%D0%B0%D1%82%D0%BA%D0%BE%D0%B2%D0%B0_%D0%B0%D0%BB%D0%B3%D0%B5%D0%B1%D1%80%D0%B0/01%3A_%D0%A0%D0%B5%D0%B0%D0%BB%D1%8C%D0%BD%D1%96_%D1%87%D0%B8%D1%81%D0%BB%D0%B0_%D1%82%D0%B0_%D1%97%D1%85_%D0%BE%D0%BF%D0%B5%D1%80%D0%B0%D1%86%D1%96%D1%97/1.07%3A_%D0%9F%D0%BE%D1%80%D1%8F%D0%B4%D0%BE%D0%BA_%D0%BE%D0%BF%D0%B5%D1%80%D0%B0%D1%86%D1%96%D0%B9
\(\begin{aligned} \left(−\frac{2}{3}\right)^{2}÷\left[\frac{5}{3}−\left(−\frac{1}{2}\right)^{3}\right]&=\left(-\frac{2}{3} \right)^{2}\div \left[\frac{5}{3}-\left(-\frac{1}{8}\right)\right] \\&=\left(...\(\begin{aligned} \left(−\frac{2}{3}\right)^{2}÷\left[\frac{5}{3}−\left(−\frac{1}{2}\right)^{3}\right]&=\left(-\frac{2}{3} \right)^{2}\div \left[\frac{5}{3}-\left(-\frac{1}{8}\right)\right] \\&=\left(-\frac{2}{3}\right)^{2}\div\left[\frac{5}{3}+\frac{1}{8}\right] \\ &=\left(-\frac{2}{3}\right)^{2}\div\left[\frac{40}{24}+\frac{3}{24}\right] \\ &=\left(-\frac{2}{3}\right)^{2}\div\frac{43}{24} \\ &=\frac{4}{\color{Cerulean}{\underset{3}{\cancel{\color{black}{9}}}}}\color{black}{\cdot\frac{\color{C…