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  • https://ukrayinska.libretexts.org/%D0%9C%D0%B0%D1%82%D0%B5%D0%BC%D0%B0%D1%82%D0%B8%D0%BA%D0%B0/%D0%90%D0%BB%D0%B3%D0%B5%D0%B1%D1%80%D0%B0/%D0%9F%D0%BE%D1%87%D0%B0%D1%82%D0%BA%D0%BE%D0%B2%D0%B0_%D0%B0%D0%BB%D0%B3%D0%B5%D0%B1%D1%80%D0%B0/08%3A_%D0%A0%D0%B0%D0%B4%D0%B8%D0%BA%D0%B0%D0%BB%D1%8C%D0%BD%D1%96_%D0%B2%D0%B8%D1%80%D0%B0%D0%B7%D0%B8_%D1%82%D0%B0_%D1%80%D1%96%D0%B2%D0%BD%D1%8F%D0%BD%D0%BD%D1%8F/8.05%3A_%D0%A0%D0%B0%D1%86%D1%96%D0%BE%D0%BD%D0%B0%D0%BB%D1%8C%D0%BD%D1%96_%D0%BF%D0%BE%D0%BA%D0%B0%D0%B7%D0%BD%D0%B8%D0%BA%D0%B8
    \(\begin{aligned} \frac{x^{1 / 2}}{x^{1 / 3}} &=x^{\frac{1}{2}-\frac{1}{3}}\qquad\color{Cerulean}{Apply\:the\:quotient\:rule\:\frac{x^{m}}{x^{n}}=x^{m-n}.} \\ &=x^{\frac{3}{6}-\frac{2}{6}} \qquad\colo...\(\begin{aligned} \frac{x^{1 / 2}}{x^{1 / 3}} &=x^{\frac{1}{2}-\frac{1}{3}}\qquad\color{Cerulean}{Apply\:the\:quotient\:rule\:\frac{x^{m}}{x^{n}}=x^{m-n}.} \\ &=x^{\frac{3}{6}-\frac{2}{6}} \qquad\color{Cerulean}{Find\:equivalent\:fractions\:with\:a\:common\:denominator\:and\:then\:subtract.} \\ &=x^{\frac{1}{6}} \end{aligned}\)