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    16x=25log16x=log25xlog16=log25x=log25log16x=1.16 \(\begin{aligned} \log (x+1)^{(x-4)} &=\log 1 \\(x-4) \cdot \lo...16x=25log16x=log25xlog16=log25x=log25log16x=1.16 log(x+1)(x4)=log1(x4)log(x+1)=0x4=0 or log(x+1)=0x=4 or (x+1)=100=1x=4,0 exex3=14ex(exex)=(42)exe2x1=42ex(ex)242ex1=0