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    z+93^ {\ circ} &=180^ {\ circ} & x =\ розриву {1} {2}\ ліворуч (58^ {\ circ} +106^ {\ circ}\ праворуч) & y+82^ {\ circ} &= 180^ {\ circ}\ \(\begin{aligned}m\angle A&=\dfrac{1}{2}m\widehat{BD}=12(115+8...z+93^ {\ circ} &=180^ {\ circ} & x =\ розриву {1} {2}\ ліворуч (58^ {\ circ} +106^ {\ circ}\ праворуч) & y+82^ {\ circ} &= 180^ {\ circ}\ \(\begin{aligned}m\angle A&=\dfrac{1}{2}m\widehat{BD}=12(115+86)=100.5^{\circ} \\ m\angle B&=\dfrac{1}{2}m\widehat{AC}=12(86+105)=95.5^{\circ} \\ m\angle C&=180^{\circ}−m\angle A=180^{\circ}−100.5^{\circ}=79.5^{\circ} \\ m\angle D&=180^{\circ}−m\angle B=180^{\circ}−95.5^{\circ}=84.5^{\circ}\end{aligned}\)