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8.8 Правило Крамера
https://ukrayinska.libretexts.org/%D0%94%D0%BE%D0%BA%D0%BE%D0%BB%D0%B5%D0%B4%D0%B6%D0%BD%D0%B0_%D0%BE%D1%81%D0%B2%D1%96%D1%82%D0%B0/%D0%9C%D0%B0%D1%82%D0%B5%D0%BC%D0%B0%D1%82%D0%B8%D0%BA%D0%B0/%D0%9F%D0%BE%D0%BF%D0%B5%D1%80%D0%B5%D0%B4%D0%BD%D1%94_%D0%BE%D0%B1%D1%87%D0%B8%D1%81%D0%BB%D0%B5%D0%BD%D0%BD%D1%8F/08%3A_%D0%A1%D0%B8%D1%81%D1%82%D0%B5%D0%BC%D0%B8_%D1%82%D0%B0_%D0%BC%D0%B0%D1%82%D1%80%D0%B8%D1%86%D1%96/8.8_%D0%9F%D1%80%D0%B0%D0%B2%D0%B8%D0%BB%D0%BE_%D0%9A%D1%80%D0%B0%D0%BC%D0%B5%D1%80%D0%B0
\(y=\frac{\left|\begin{array}{lll}a & j & c \\ d & k & f \\ g & l & i\end{array}\right|}{\left|\begin{array}{lll}a & b & c \\ d & e & f \\ g & h & i\end{array}\right|}=\frac{\left|\begin{array}{ccc}1 ...\(y=\frac{\left|\begin{array}{lll}a & j & c \\ d & k & f \\ g & l & i\end{array}\right|}{\left|\begin{array}{lll}a & b & c \\ d & e & f \\ g & h & i\end{array}\right|}=\frac{\left|\begin{array}{ccc}1 & 0 & -1 \\ 7 & 14 & 1 \\ 0 & 10 & 1\end{array}\right|}{\left|\begin{array}{ccc}1 & 2 & -1 \\ 7 & 0 & 1 \\ 0 & 1 & 1\end{array}\right|}=\frac{14+0+(-70)-0-10-0}{0+0+(-7)-0-1-14}=\frac{-66}{-22}=3\)