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4.8: Застосування базової тригонометрії трикутника
https://ukrayinska.libretexts.org/%D0%94%D0%BE%D0%BA%D0%BE%D0%BB%D0%B5%D0%B4%D0%B6%D0%BD%D0%B0_%D0%BE%D1%81%D0%B2%D1%96%D1%82%D0%B0/%D0%9C%D0%B0%D1%82%D0%B5%D0%BC%D0%B0%D1%82%D0%B8%D0%BA%D0%B0/%D0%9F%D0%BE%D0%BF%D0%B5%D1%80%D0%B5%D0%B4%D0%BD%D1%94_%D0%BE%D0%B1%D1%87%D0%B8%D1%81%D0%BB%D0%B5%D0%BD%D0%BD%D1%8F/04%3A_%D0%9E%D1%81%D0%BD%D0%BE%D0%B2%D0%BD%D0%B0_%D1%82%D1%80%D0%B8%D0%B3%D0%BE%D0%BD%D0%BE%D0%BC%D0%B5%D1%82%D1%80%D1%96%D1%8F_%D1%82%D1%80%D0%B8%D0%BA%D1%83%D1%82%D0%BD%D0%B8%D0%BA%D0%B0/4.08%3A_%D0%97%D0%B0%D1%81%D1%82%D0%BE%D1%81%D1%83%D0%B2%D0%B0%D0%BD%D0%BD%D1%8F_%D0%B1%D0%B0%D0%B7%D0%BE%D0%B2%D0%BE%D1%97_%D1%82%D1%80%D0%B8%D0%B3%D0%BE%D0%BD%D0%BE%D0%BC%D0%B5%D1%82%D1%80%D1%96%D1%97_%D1%82%D1%80%D0%B8%D0%BA%D1%83%D1%82%D0%BD%D0%B8%D0%BA%D0%B0
\(\begin{aligned} h=\tan \alpha(507+x) &=x \tan \beta \\ 507 \tan \alpha+x \tan \alpha &=x \tan \beta \\ 507 \tan \alpha &=x \tan \beta-x \tan \alpha \\ 507 \tan \alpha &=x(\tan \beta-\tan \alpha) \\ ...\(\begin{aligned} h=\tan \alpha(507+x) &=x \tan \beta \\ 507 \tan \alpha+x \tan \alpha &=x \tan \beta \\ 507 \tan \alpha &=x \tan \beta-x \tan \alpha \\ 507 \tan \alpha &=x(\tan \beta-\tan \alpha) \\ x=\frac{507 \tan \alpha}{\tan \beta-\tan \alpha} &=\frac{507 \tan 21.567^{\circ}}{\tan 25.683^{\circ}-\tan 21.567^{\circ}} \approx 2340 \text { meters} \end{aligned}\)