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3.7: Логістичні функції
https://ukrayinska.libretexts.org/%D0%94%D0%BE%D0%BA%D0%BE%D0%BB%D0%B5%D0%B4%D0%B6%D0%BD%D0%B0_%D0%BE%D1%81%D0%B2%D1%96%D1%82%D0%B0/%D0%9C%D0%B0%D1%82%D0%B5%D0%BC%D0%B0%D1%82%D0%B8%D0%BA%D0%B0/%D0%9F%D0%BE%D0%BF%D0%B5%D1%80%D0%B5%D0%B4%D0%BD%D1%94_%D0%BE%D0%B1%D1%87%D0%B8%D1%81%D0%BB%D0%B5%D0%BD%D0%BD%D1%8F/03%3A_%D0%96%D1%83%D1%80%D0%BD%D0%B0%D0%BB%D0%B8_%D1%82%D0%B0_%D0%B5%D0%BA%D1%81%D0%BF%D0%BE%D0%BD%D0%B5%D0%BD%D1%82%D0%B8/3.07%3A_%D0%9B%D0%BE%D0%B3%D1%96%D1%81%D1%82%D0%B8%D1%87%D0%BD%D1%96_%D1%84%D1%83%D0%BD%D0%BA%D1%86%D1%96%D1%97
\(\begin{aligned} 0.05 &=\frac{1}{1+a \cdot b^{0}} \\ 1+a &=\frac{1}{0.05} \\ a &=19 \\ 0.95 &=\frac{1}{1+19 \cdot b^{20}} \\ 1+19 \cdot b^{20} &=\frac{1}{0.95} \\ b^{20} &=\frac{\left(\frac{1}{0.95}-... $\begin{aligned} 0.05 &=\frac{1}{1+a \cdot b^{0}} \\ 1+a &=\frac{1}{0.05} \\ a &=19 \\ 0.95 &=\frac{1}{1+19 \cdot b^{20}} \\ 1+19 \cdot b^{20} &=\frac{1}{0.95} \\ b^{20} &=\frac{\left(\frac{1}{0.95}-1\right)}{19} \\ b & \approx 0.74495 \end{aligned}$