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  • https://ukrayinska.libretexts.org/%D0%86%D0%BD%D0%B6%D0%B5%D0%BD%D0%B5%D1%80%D0%BD%D0%B0/%D0%9C%D0%B0%D1%88%D0%B8%D0%BD%D0%BE%D0%B1%D1%83%D0%B4%D1%83%D0%B2%D0%B0%D0%BD%D0%BD%D1%8F/%D0%91%D1%83%D0%B4%D1%96%D0%B2%D0%B5%D0%BB%D1%8C%D0%BD%D0%B0_%D0%BC%D0%B5%D1%85%D0%B0%D0%BD%D1%96%D0%BA%D0%B0_(Wierzbicki)/01%3A_%D0%9F%D0%BE%D0%BD%D1%8F%D1%82%D1%82%D1%8F_%D1%88%D1%82%D0%B0%D0%BC%D1%83/1.08%3A_%D0%A0%D0%BE%D0%B7%D1%88%D0%B8%D1%80%D0%B5%D0%BD%D0%B0_%D1%84%D0%BE%D1%80%D0%BC%D0%B0_%D1%81%D0%BF%D1%96%D0%B2%D0%B2%D1%96%D0%B4%D0%BD%D0%BE%D1%88%D0%B5%D0%BD%D0%BD%D1%8F_%D0%B4%D0%B5%D1%84%D0%BE%D1%80%D0%BC%D0%B0%D1%86%D1%96%D1%97-%D0%B7%D0%BC%D1%96%D1%89%D0%B5%D0%BD%D0%BD%D1%8F
    \[\alpha = 1, \beta = 1 \; x_1 = x, \; \epsilon_{xx}^{\circ} = \frac{1}{2} \left( \frac{\partial u_{x}^{\circ}}{\partial x} + \frac{\partial u_{x}^{\circ}}{\partial x} \right) = \frac{\partial u_{x}^{...α=1,β=1x1=x,ϵxx=12(uxx+uxx)=uxx α=1,β=1x1=xκxx=2wx2=x(wx)=x(θx)