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  • https://ukrayinska.libretexts.org/%D0%86%D0%BD%D0%B6%D0%B5%D0%BD%D0%B5%D1%80%D0%BD%D0%B0/%D0%95%D0%BB%D0%B5%D0%BA%D1%82%D1%80%D0%BE%D1%82%D0%B5%D1%85%D0%BD%D1%96%D0%BA%D0%B0/%D0%95%D0%BB%D0%B5%D0%BA%D1%82%D1%80%D0%BE%D0%BE%D0%BF%D1%82%D0%B8%D0%BA%D0%B0/%D0%9F%D1%80%D1%8F%D0%BC%D0%B0_%D0%B5%D0%BD%D0%B5%D1%80%D0%B3%D1%96%D1%8F_(Mitofsky)/11%3A_%D0%9E%D0%B1%D1%87%D0%B8%D1%81%D0%BB%D0%B5%D0%BD%D0%BD%D1%8F_%D0%B2%D0%B0%D1%80%D1%96%D0%B0%D1%86%D1%96%D0%B9/11.05%3A_%D0%9F%D1%80%D0%B8%D0%BA%D0%BB%D0%B0%D0%B4_%D1%96%D0%BD%D0%B4%D1%83%D0%BA%D1%82%D0%BE%D1%80%D0%B0_%D0%BA%D0%BE%D0%BD%D0%B4%D0%B5%D0%BD%D1%81%D0%B0%D1%82%D0%BE%D1%80%D0%B0
    \[H\left(t, Q, \frac{d Q}{d t}\right)=\frac{1}{2 C} Q^{2}+\frac{1}{2} L\left(\frac{d Q}{d t}\right)^{2} \nonumber \] \[\mathcal{L}\left(t, Q, \frac{d Q}{d t}\right)=\frac{1}{2 C} Q^{2}-\frac{1}{2} L\l...\[H\left(t, Q, \frac{d Q}{d t}\right)=\frac{1}{2 C} Q^{2}+\frac{1}{2} L\left(\frac{d Q}{d t}\right)^{2} \nonumber \] \[\mathcal{L}\left(t, Q, \frac{d Q}{d t}\right)=\frac{1}{2 C} Q^{2}-\frac{1}{2} L\left(\frac{d Q}{d t}\right)^{2} \nonumber \] \[\frac{\partial \mathcal{L}}{\partial Q}-\frac{d}{d t} \frac{\partial \mathcal{L}}{\partial\left(\frac{d Q}{d t}\right)}=0. \label{11.5.14} \] \[\mathbb{M}=\frac{\partial \mathcal{L}}{\partial\left(\frac{d Q}{d t}\right)}=-L \frac{d Q}{d t} \nonumber \]