Search Back to top Filter ResultsLocationфізики (2)ClassificationArticle typeBook or UnitChapterSection or PageN/AN/AShow Page TOCYes on PageNo on PageCover PageSet Cover Page/Add to Download CenterSet Cover Page/Not in Download CenterCompile but don't publishLicensePublic DomainCC BYCC BY-SACC BY-NC-SACC BY-NDCC BY-NC-NDGNU GPLAll Rights ReservedCC BY-NCGNU FDLMixed LicensesCK-12Caltech LicenseCollectionTranscludedyesLicense Version1.02.02.53.04.01.3Include attachmentsContent TypeDocumentImageOther Searching inAll resultsAbout 2 results15.3: Періодичний рухhttps://ukrayinska.libretexts.org/%D1%84%D1%96%D0%B7%D0%B8%D0%BA%D0%B8/%D0%A3%D0%BD%D1%96%D0%B2%D0%B5%D1%80%D1%81%D0%B8%D1%82%D0%B5%D1%82%D1%81%D1%8C%D0%BA%D0%B0_%D1%84%D1%96%D0%B7%D0%B8%D0%BA%D0%B0/%D0%9A%D0%BD%D0%B8%D0%B3%D0%B0%3A_%D0%A4%D1%96%D0%B7%D0%B8%D0%BA%D0%B0_(Boundless)/15%3A_%D0%A5%D0%B2%D0%B8%D0%BB%D1%96_%D1%82%D0%B0_%D0%B2%D1%96%D0%B1%D1%80%D0%B0%D1%86%D1%96%D1%97/15.3%3A_%D0%9F%D0%B5%D1%80%D1%96%D0%BE%D0%B4%D0%B8%D1%87%D0%BD%D0%B8%D0%B9_%D1%80%D1%83%D1%85Період - це тривалість одного циклу в повторюваному заході, тоді як частота - це кількість циклів за одиницю часу.23.3: Енергія та простий гармонійний осциляторhttps://ukrayinska.libretexts.org/%D1%84%D1%96%D0%B7%D0%B8%D0%BA%D0%B8/%D0%9A%D0%BB%D0%B0%D1%81%D0%B8%D1%87%D0%BD%D0%B0_%D0%BC%D0%B5%D1%85%D0%B0%D0%BD%D1%96%D0%BA%D0%B0/%D0%9A%D0%BB%D0%B0%D1%81%D0%B8%D1%87%D0%BD%D0%B0_%D0%BC%D0%B5%D1%85%D0%B0%D0%BD%D1%96%D0%BA%D0%B0_(Dourmashkin)/23%3A_%D0%9F%D1%80%D0%BE%D1%81%D1%82%D0%B8%D0%B9_%D0%B3%D0%B0%D1%80%D0%BC%D0%BE%D0%BD%D1%96%D0%B9%D0%BD%D0%B8%D0%B9_%D1%80%D1%83%D1%85/23.03%3A_%D0%95%D0%BD%D0%B5%D1%80%D0%B3%D1%96%D1%8F_%D1%82%D0%B0_%D0%BF%D1%80%D0%BE%D1%81%D1%82%D0%B8%D0%B9_%D0%B3%D0%B0%D1%80%D0%BC%D0%BE%D0%BD%D1%96%D0%B9%D0%BD%D0%B8%D0%B9_%D0%BE%D1%81%D1%86%D0%B8%D0%BB%D1%8F%D1%82%D0%BE%D1%80\[\frac{d \theta}{d t}\left(t_{1}\right)=-\sqrt{\frac{g}{l}} \theta_{0} \sin \left(\sqrt{\frac{g}{l}} t_{1}\right)=-\sqrt{\frac{g}{l}} \theta_{0} \sin \left(\frac{\pi}{2}\right)=-\sqrt{\frac{g}{l}} \t...dθdt(t1)=−√glθ0sin(√glt1)=−√glθ0sin(π2)=−√glθ0 vθ(t1)≡v1=ldθdt(t1)=−l√glθ0sin(√glt1)=−√lgθ0sin(π2)=−√lgθ0⋅(23.3.32)MoreShow more results