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  • https://ukrayinska.libretexts.org/%D0%9C%D0%B0%D1%82%D0%B5%D0%BC%D0%B0%D1%82%D0%B8%D0%BA%D0%B0/%D0%90%D0%BD%D0%B0%D0%BB%D1%96%D0%B7/%D0%9A%D0%BD%D0%B8%D0%B3%D0%B0%3A_%D0%91%D1%83%D0%BA%D0%B2%D0%B0%D1%80_%D1%80%D0%B5%D0%B0%D0%BB%D1%8C%D0%BD%D0%BE%D0%B3%D0%BE_%D0%B0%D0%BD%D0%B0%D0%BB%D1%96%D0%B7%D1%83_(Sloughter)/04%3A_%D0%A2%D0%BE%D0%BF%D0%BE%D0%BB%D0%BE%D0%B3%D1%96%D1%8F_%D1%80%D0%B5%D0%B0%D0%BB%D1%8C%D0%BD%D0%BE%D1%97_%D0%BB%D1%96%D0%BD%D1%96%D1%97/4.01%3A_%D0%86%D0%BD%D1%82%D0%B5%D1%80%D0%B2%D0%B0%D0%BB%D0%B8
    (a,b)={x:xR,a<x<b} [a,b]={x:xR,axb}, (,b]={x:xR,xb}, [a,+)={x:xR,xa} \[(...(a,b)={x:xR,a<x<b} [a,b]={x:xR,axb}, (,b]={x:xR,xb}, [a,+)={x:xR,xa} (a,b]={x:xR,a<xb} [a,b)={x:xR,ax<b}, (a,b)={x:x=λa+(1λ)b,0<λ<1}. x=(bxba)a+(xaba)b=(bxba)a+(1bxba)b