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    \[ \lim_{x \to ∞} \frac{x^2−4}{x^2−2x−8}= \lim_{x \to ∞} \frac{ \frac{x^2}{x^2}−\frac{4}{x^2}} {\frac{x^2}{x^2}−\frac{2x}{x^2}−\frac{8}{x^2}}=\lim_{x \to ∞} \frac{1−\frac{4}{x^2}}{1−\frac{2}{x}−\frac{...limxx24x22x8=limxx2x24x2x2x22xx28x2=limx14x212x8x2=1. Функція може бути врахованаf(x)=x3+2x2x2=x2(x+2)1(x+2)=(x21)(x+2)=(x1)(x+1)(x+2)