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  • https://ukrayinska.libretexts.org/%D1%84%D1%96%D0%B7%D0%B8%D0%BA%D0%B8/%D0%9A%D0%BB%D0%B0%D1%81%D0%B8%D1%87%D0%BD%D0%B0_%D0%BC%D0%B5%D1%85%D0%B0%D0%BD%D1%96%D0%BA%D0%B0/%D0%92%D0%B8%D0%BF%D1%83%D1%81%D0%BA%D0%BD%D0%B8%D0%BA_%D0%BA%D0%BB%D0%B0%D1%81%D0%B8%D1%87%D0%BD%D0%BE%D1%97_%D0%BC%D0%B5%D1%85%D0%B0%D0%BD%D1%96%D0%BA%D0%B8_(Fowler)/28%3A_%D0%A0%D1%96%D0%B2%D0%BD%D1%8F%D0%BD%D0%BD%D1%8F_%D0%95%D0%B9%D0%BB%D0%B5%D1%80%D0%B0/28.04%3A_%D0%90%D1%81%D0%B8%D0%BC%D0%B5%D1%82%D1%80%D0%B8%D1%87%D0%BD%D0%B8%D0%B9_%D0%B2%D0%B5%D1%80%D1%85
    \[ \begin{array}{r}\dfrac{L_{1}^{2}}{I_{1}}+\dfrac{L_{2}^{2}}{I_{2}}+\dfrac{L_{3}^{2}}{I_{3}}=2 E \\\dfrac{L_{1}^{2}}{I_{2}}+\dfrac{L_{2}^{2}}{I_{2}}+\dfrac{L_{3}^{2}}{I_{2}}=\dfrac{L^{2}}{I_{2}}=2 E\...L21I1+L22I2+L23I3=2EL21I2+L22I2+L23I2=L2I2=2E L21(1I11I2)+L23(1I31I2)=0 L1=±cL3,c=I1(I3I2)/I2(I2I1)