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  • 3: Симетричні групи
    https://ukrayinska.libretexts.org/%D0%9C%D0%B0%D1%82%D0%B5%D0%BC%D0%B0%D1%82%D0%B8%D0%BA%D0%B0/%D0%90%D0%B1%D1%81%D1%82%D1%80%D0%B0%D0%BA%D1%82%D0%BD%D0%B0_%D1%82%D0%B0_%D0%B3%D0%B5%D0%BE%D0%BC%D0%B5%D1%82%D1%80%D0%B8%D1%87%D0%BD%D0%B0_%D0%B0%D0%BB%D0%B3%D0%B5%D0%B1%D1%80%D0%B0/%D0%95%D0%BB%D0%B5%D0%BC%D0%B5%D0%BD%D1%82%D0%B0%D1%80%D0%BD%D0%B0_%D0%B0%D0%B1%D1%81%D1%82%D1%80%D0%B0%D0%BA%D1%82%D0%BD%D0%B0_%D0%B0%D0%BB%D0%B3%D0%B5%D0%B1%D1%80%D0%B0_(Clark)/01%3A_%D0%93%D0%BB%D0%B0%D0%B2%D0%B8/1.03%3A_%D0%A1%D0%B8%D0%BC%D0%B5%D1%82%D1%80%D0%B8%D1%87%D0%BD%D1%96_%D0%B3%D1%80%D1%83%D0%BF%D0%B8
    Дозвольтеσ іτ визначитися наступним чином:\[\sigma= \left ( \begin{array} {ccc} 1&2&3\\ 2&1&3 \end{array} \right ), \quad \quad \tau = \left ( \begin{array} {ccc} 1&2&3\\ 2&3&1 \end{ar...Дозвольтеσ іτ визначитися наступним чином:σ=(123213),τ=(123231) Звідси випливає, щоστ(1)=σ(τ(1))=σ(2)=1στ(2)=σ(τ(2))=σ(3)=3στ(3)=σ(τ(3))=σ(1)=2 Таким чином, ми\[\sigma\tau = \left ( \begin{array} {ccc} 1&2&3\\ 1&3…