Search

Молярність
https://ukrayinska.libretexts.org/%D0%A5%D1%96%D0%BC%D1%96%D1%8F/%D0%97%D0%B0%D0%B3%D0%B0%D0%BB%D1%8C%D0%BD%D0%B0_%D1%85%D1%96%D0%BC%D1%96%D1%8F/%D0%9A%D0%BD%D0%B8%D0%B3%D0%B0%3A_%D0%97%D0%B0%D0%B3%D0%B0%D0%BB%D1%8C%D0%BD%D0%B0_%D1%85%D1%96%D0%BC%D1%96%D1%87%D0%BD%D0%B0_%D0%B4%D0%BE%D0%B1%D0%B0%D0%B2%D0%BA%D0%B0_(Eames)/%D0%A0%D0%BE%D0%B7%D1%80%D0%B0%D1%85%D1%83%D0%BD%D0%BA%D0%B8_%D1%85%D1%96%D0%BC%D1%96%D1%97/%D0%9C%D0%BE%D0%BB%D1%8F%D1%80%D0%BD%D1%96%D1%81%D1%82%D1%8C
\[\left(\dfrac{32\; \cancel{g\; HCl}}{100\; \cancel{g\; solution}}\right) \left(\dfrac{1\; mol\; HCl}{36.46\; \cancel{g\; HCl}}\right) \left(\dfrac{1.1593\; \cancel{g}}{1\; \cancel{mL\; solution}}\rig... $\left(\dfrac{32\; \cancel{g\; HCl}}{100\; \cancel{g\; solution}}\right) \left(\dfrac{1\; mol\; HCl}{36.46\; \cancel{g\; HCl}}\right) \left(\dfrac{1.1593\; \cancel{g}}{1\; \cancel{mL\; solution}}\right) \left(\dfrac{\cancel{1000\; mL}}{1\; L}\right)=10\; M\; HCl$ $(1\; \cancel{L\; of\; 2.5\; M\; HCl}) \left(\dfrac{2.5\; \cancel{mol\; HCl}}{1\; \cancel{L\; of\; 2.5\; M\; HCl}}\right) \left(\dfrac{1000\; mL\; of\; 10\; M\; HCl}{10\; \cancel{mol\; HCl}}\right)=250\; mL\; of\; 10\; M\; HCl$